5x^2+1.6x-1.6=0

Solution for 5x^2+1.6x-1.6=0 equation:

5x^2+1.6x-1.6=0

a = 5; b = 1.6; c = -1.6;
Δ = b2-4ac
Δ = 1.62-4·5·(-1.6)
Δ = 34.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{34.56}}{2*5}=\frac{-1.6-\sqrt{34.56}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{34.56}}{2*5}=\frac{-1.6+\sqrt{34.56}}{10}
$